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Jamb Tutorial 2016 - Mathematics Class - Forum

Solutionz
Solutionz
Welcome to Solutionclass Jamb Tutorial Centre for
Mathematics class
Lecturers in charge - Mr Solution

OVER TO YOU NOW

Eng hamzzy

Mr Solution
Mr Solution
RECOMMENDED JAMB SYLLABUS FOR MATHEMATICS

1. NUMBER BASES
2. FRACTIONS, DECIMALS, APPROXIMATIONS AND
PERCENTAGES
3. INDICES, LOGARITHMS AND SURDS
4. SETS

SECTION II: ALGEBRA

1. POLYNOMIALS
2. VARIATION
3. INEQUALITIES
4. PROGRESSION
5. BINARY OPERATIONS
6. MATRICES AND DETERMINANTS

SECTION III: GEOMETRIC AND TRIGONOMETRIC

1. EUCLIDEAN GEOMETRY
2. MENSURATION
3. LOCI
4. COORDINATE GEOMETRY
5. TRIGONOMETRY

SECTION IV: CALCULUS

1. DIFFERENTIATION
2. APPLICATION OF DIFFERENTIATION
3. INTEGRATION

SECTION V: STATISTICS

1. REPRESENTATION OF DATA
2. MEASURES OF LOCATION
3. MEASURES OF DISPERSION
4. PERMUTATION AND COMBINATION
5. PROBABILITY

GOOD LUCK…


Am going to start with number base.... The word number base is just talking about a number that has a base for example 5 is a number, when i put a base to d number 5,it becomes number base....


Mr Solution
Mr Solution
Nw this base am talking about is also a number, we have different base, e. g base ten, base two also called benary, base eight also called octal and mani more......


Note, whenever u are solving question concerning number base, note the highest digit of any number base is always one less than the base


Plz also note this too..... The conversion from base ten to any other base is done through division, then the conversion from other bases to base ten is done through multiplication and lastly the conversion of a number in one base to a base other than base ten is done firstly by converting that number to base ten through multiplication, then convert it to the base in question through division.... Plz all this will be clear when i begin to solve...


Mr Solution
Mr Solution
Convert 72 in base six to a number in base three(jamb past q 2012)...

The steps on how to solve that is this, firstly convert that 72 in base six to base ten through multiplication, then ur answer convert to base three through division.....

72 in base six is solved lyk this.... 7*6, d 6 has a power, the power is 1 plus 2*6 in d power of 0... 7*6=42,2*6 in power of 0=2 N/B:any number raise in power of zero is one, so that 6 in d power of 0 is 1,so 2*1=2,thats hw i got ma ans 2.so 42+2=44 in base ten

Then that 44 in base ten am converting to base three through division.......... 44/3=14 r 2,14/3=4 r 2,4/3=1 r 1,1/3=0 r 1.....N/B:that"r"means remainder, the remainder is wat we are considering as our answer, u start 4rm d least of d division to bring out d ans, remember itz d remainder we ars considering so our answer is lyk this 1122 in base three......

Mr Solution
Mr Solution
Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions

Guest
Guest
Originally posted by Mr Solution
Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions
divide both side by 5


Guest
Guest
jegede by name
My love dat question 2q3 in base 5 to base ten.
Ve nt seen dat type of convention base question before. Tanx sir

Guest
Guest
we are begining with the topic called SURD.
SURD.
A surd is an irrational number.
irrational numbers are numbers that cannot be
expressed as ratios of intergers.they are irrational
because their exact value are not determinable,only the
approximate values can be known,e.g π,√2,√7,√29 etc.

Guest
Guest
Rules of Surds
The following are the basic rules mostly used when
performing operations on surds.
Rule 1:√ab = √a × √b
Rule2 : √a/b = √a/√b
Rule3 : √a + b not equal to √a + √b
Rule4 : √a - b not equal to √a - √b
provided a and b are positive.
e.g √12 = √4 × √3 or √6 × √2 etc.
also √7/2 = √7/√2
Student should avoid the error of writing
√a+b as √a + √b or √a-b as √a - √b
as these are wrong methods of evaluations.

Guest
Guest
Basic Forms of Surds
√p is said to be in its basic form if p does not have a
factor that is a perfect square.Thus,√p will only be basic
if √p cannot be broken down further into two factors
where one of them has an exact square root.e.g
√6,√5,√7,√2,√3 are in basic forms.Here √18 is not in
basic form because it can be broken into √9 × 2
√18 = √9 ×2 = 3√2
But here 3√2 is now in a basic form.

Story Story
Story Story
15>>Similiar Surds
surds are similiar if their irrational parts contain the
same numeral,e.g
1.3√n and 5√n √n =√n
2.6√x and 3√x. √x =√
3.5√2 and 7√2. √2 =√2
Note:the following must not be taken to be similar.
1.6√3 and 4√n ; √3 is not equal to √n
2.5√2 and 2√5 ; √2 is not equal to √5

Conjugate Surds
conjugate surds are two surds whose product results in a
rational number.in an expression containing difference of
two squares,it is known that br /> (x +y)(x +y) = ×^2 -
y^,
in a similiar manner
(√x + √y)(√x - √y) = {√x)^2 - (√y)^2 = x -y
e.g
i.the conjugate of √3 -√5 = √3 + √5
ii.the conjugate of -2√7 + √3 = -2√7 - √3
in general: The conjugate of √x + √y is √x -√y
The conjugate of √x - √y is √x + √y.


>Simplification of Surds
Surds can be simplified either in their simplest form or as
a single surd.
Examples
1. Simplify (a) √45 (b) √98
Solution
a. √45 = √9 × 5 = √9 × √5 = 3√5
b.√98 = √49 × 2 = √49 × √2 = 7√2
2.Express the following as single surds
a.2√5
b.17√2
Solution
(a). 2√5
=√4×5 = √20
(b). 17√2
=√17^2 ×2 = √578



Addition and subtraction of Surds
Note: only surds in the same basic form can either be
added or subtracted.sometimes,there may be need to
simplify such surds before doing either the addition or
the subtraction.
Examples
1. evaluate √32 + 3√8
solution
firstly u simplify the surd,which is
√16 ×2 + 3√4×2
=4√2 +(3×2)√2
=4√2 + 6√2
since they are sharing similiar surds,you can add them
which gives
=10√2
2.Evaluate 7√3 - √75
Solution:firstly simplify the surd,which gives
=7√3 - √25 × 3
=7√3 - 5√3
since they are sharing similiar surds,you subtract,which
gives
=2√3
3.Evaluate 3√48 - √75 + 2√12
solution:3√16 × 3 - √25×3 + 2√4 ×3
= {3×4)√3 } - 5√3 + (2×2)√3
= 12√3 - 5√3 + 4√3 since they have similiar surds,you
can add nd subtract.
7√3 + 4√3
=11√3

Story Story
Story Story
Multiplication and Division of surds
Examples
1.Simplify √45 × √28
solution : √9×5 × √4×7
=3√5 × 2√7
n/b:when dealing with multiplication nd division,when the
surds are not similiar you can multiply or divide it
irrespective of the difference in the surds.this is what am
saying
3×2√5×7
=6√35

2.Evaluate √24 / √50
solution: √24 / √50
= √24/50
=bring the value to the lowest,which we will have
=√12 / 25
=√12 / √25
= √4×3 / 5
= 2√3 / 5

3. Simplify √60 × √180 / √75
solutions
√60 × √180 /√ 75
= √60× 180 / √75
=√10800/ √75
=√144 = 12

4.find the square of √3 + √2
Solution br /> square of (√3 + √2) = (√3 +√2)^2
simplify which gives
√3(√3 + √2) + √2 (√3 + √2)
3 + √6 + √6 + 2
= 3+ 2√6 +2
collect like terms
3 +2 +2√6
=5 + 2√6.




Surds Rationalisation
Rationaliasation of surds is concerned with the process
of removing irrational number from the
denominator.Consider the surd 2/√3 is an irrational
number dividing a rational number.Here,both the
numerator and the denominator must be multiplied by
√3,the denominator,for it to be removed.
Examples

1.simplify 2/ 5√3
solution br /> 2/5√3
use the denominator √3 to multiply both the numerator
and the denominator,which will give
2/5√3 ×√3 / √3
we will have
2√3 / 5√9
= 2√3 / 5×3
=2/3 / 15

2. Evaluate 3/ √3 + √2
solution br /> using the conjugate of √3 +√2 to
rationalise,but this surd √3 + √ 2 will be changed to √3 -
√2 when we begin to rationalise.we re going to have
3/√3 + √2 × √3 - √2 / √3 - √2
we have
=3√3 - 3√2 divided by √ 9 - √6 + √6 - √4
=3√3 - 3√2 divided by 3 - 2
we have
3√3 - 3√2 divided by 1
so we have
3√3 - 3√2
both are sharing dsame factor so bring one out nd put
them in a fractional way.what i mean is this
3√3 - 3√2
3 (√3 - √2)

Guest
Guest
Originally posted by Mr Solution
Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions

Guest
Guest
Your Text Can Not Be Published Because It Contains A Link That We Consider As Spam

Dont Spam Here

Guest

sally
sally
pls can we find any easy way 2 solve d qestion so as not 2 waste much tym

Guest

[email protected]
[email protected]
[color=#ffff00][quote=Solutionz][color=#000000]Welcome to Solutionclass Jamb Tutorial Centre for
Mathematics class
Lecturers in charge - Mr Solution

OVER TO YOU NOW[/color][/quote][/color]

Guest

Guest
Guest
Prime needs differentiation nd calculus

Guest
Guest
Your Text Can Not Be Published Because It Contains A Link That We Consider As Spam

Dont Spam Here

Guest
Guest
Sir pls i have a que.if the end point of one side of square RSTU are R(-1,-1) and S(3,-1).find the area of the square

Guest
Guest
Originally posted by Solutionz
Welcome to Solutionclass Jamb Tutorial Centre for
Mathematics class
Lecturers in charge - Mr Solution

OVER TO YOU NOW

Guest
Guest
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'07065540016' we dèliver answèrs 4hrs before yoûr
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Guest
Guest
[color=#ff00ff][quote=Guest][quote=Mr Solution][color=#804000]Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions[/color][/quote]divide both side by 5

[/quote][/color]

Guest

Guest
Guest
I really need calculation on calculus and d rest of other which hav't work out on d curriculum

Guest
Guest
[color=#ff00ff][quote=Mr Solution][color=#804000]Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions[/color][/quote][/color]

Guest
Guest
plz i need the calculation on calculus. As in how to solve it.

Guest
Guest
Your Text Can Not Be Published Because It Contains A Link That We Consider As Spam

Dont Spam Here

[email protected]

Guest
Guest
Originally posted by Guest
we are begining with the topic called SURD.
SURD.
A surd is an irrational number.
irrational numbers are numbers that cannot be
expressed as ratios of intergers.they are irrational
because their exact value are not determinable,only the
approximate values can be known,e.g π,√2,√7,√29 etc.

correct

Guest
Guest
[color=#000000][quote=Solutionz][color=#000000]Welcome to Solutionclass Jamb Tutorial Centre for
Mathematics class
Lecturers in charge - Mr Solution

OVER TO YOU NOW[/color][/quote][/color]

Beauty @solutionclass.com

Guest
Guest
[color=#ff00ff][quote=Mr Solution][color=#804000]Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions[/color][/quote][/color]

Guest

Guest
Guest
[quote=Solutionz][color=#000000]Welcome to Solutionclass Jamb Tutorial Centre for
Mathematics class
Lecturers in charge - Mr Solution

OVER TO YOU NOW[/red][/na me]

Guest
Guest
pls i nid 2016 mathematicd waec question

Guest
Guest
[color=#990000][quote=Guest][quote=Mr Solution][color=#804000]Anoda question: 2q3 in base 5=77 in base 8 find q?

This is how to solve that, just lyk u said u will convert all to base ten...
2q3 in base 5 to base ten
2*5r2 +q*5r1 +3*5r0=7*8r1 + 7*8r0
2*25 +5q + 3=7*8 +7*1
50 +5q+3=56 +7
Collect lyk terms
50 + 3 +5q=63
53 +5q=63
5q=63-53
5q=10,
Divide both sides by 5 so that 'q' can stand alone, so the ans is q=2

pls ask questions[/color][/quote][/quote][/color]


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